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Remove deprecated defaults() function

tags/2019.12
Hypolite Petovan 1 year ago
parent
commit
f65ebb937c
1 changed files with 0 additions and 41 deletions
  1. +0
    -41
      boot.php

+ 0
- 41
boot.php View File

@@ -322,47 +322,6 @@ function get_app()
return BaseObject::getApp();
}

/**
* Return the provided variable value if it exists and is truthy or the provided
* default value instead.
*
* Works with initialized variables and potentially uninitialized array keys
*
* Usages:
* - defaults($var, $default)
* - defaults($array, 'key', $default)
*
* @param array $args
* @brief Returns a defaut value if the provided variable or array key is falsy
* @return mixed
* @deprecated since version 2019.06, use native coalesce operator (??) instead
*/
function defaults(...$args)
{
if (count($args) < 2) {
throw new BadFunctionCallException('defaults() requires at least 2 parameters');
}
if (count($args) > 3) {
throw new BadFunctionCallException('defaults() cannot use more than 3 parameters');
}
if (count($args) === 3 && is_null($args[1])) {
throw new BadFunctionCallException('defaults($arr, $key, $def) $key is null');
}

// The default value always is the last argument
$return = array_pop($args);

if (count($args) == 2 && is_array($args[0]) && !empty($args[0][$args[1]])) {
$return = $args[0][$args[1]];
}

if (count($args) == 1 && !empty($args[0])) {
$return = $args[0];
}

return $return;
}

/**
* @brief Used to end the current process, after saving session state.
* @deprecated


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